Physics · Lesson 19
Viscosimeter
Drop a steel ball into a column of fluid and time its fall. The slower it falls, the thicker the fluid. This simple technique — Stokes' viscosimetry — lets engineers measure the viscosity of everything from water to motor oil to honey, using only a ball, a ruler, and a stopwatch.
Who Was George Gabriel Stokes?
George Gabriel Stokes (1819–1903) was an Irish mathematician and physicist at Cambridge University. In 1851 he derived the drag force on a sphere moving through a viscous fluid — what we now call Stokes' Law. His work is foundational to fluid mechanics, meteorology (how raindrops fall), and particle physics (how droplets behave in bubble chambers). Robert Millikan later used Stokes' Law in his famous oil-drop experiment to measure the charge of an electron.
Stokes' Law & Terminal Velocity
When a sphere falls through a viscous fluid, three forces act on it: gravity (down), buoyancy (up), and drag (up). At terminal velocity, these forces balance and the sphere moves at a constant speed.
Rearranged to find viscosity from a measured terminal velocity: η = 2r²(ρs − ρf)g / (9vt)
| Fluid | Viscosity (Pa·s) | Density (kg/m³) |
|---|---|---|
| Water (20°C) | 0.001 | 998 |
| Motor oil (SAE 30) | 0.10 | 880 |
| Glycerol | 1.40 | 1260 |
| Honey | 10.0 | 1400 |
Interactive Viscosimeter
Select a fluid and sphere, then drop the sphere to observe terminal velocity.
Real-World Applications
Practice Problems
Use vt = 2r²(ρs−ρf)g / 9η and Stokes drag F = 6πηrv.
Easy1. Terminal velocity is reached when the drag force plus buoyancy equals the gravitational force. True or False?
Easy2. Which fluid has the highest viscosity?
Medium3. Stokes' Law: F = 6πηrv. A sphere of r = 0.002 m falls at v = 0.01 m/s in glycerol (η = 1.4 Pa·s). What is the drag force? (Answer in scientific notation ×10⁻⁴ N, 2 sig figs.)
Medium4. The same sphere falls in honey (100× more viscous than glycerol). Compared to glycerol, its terminal velocity would be approximately:
Challenge5. A steel sphere (r = 1 mm = 0.001 m, ρs = 7800 kg/m³) falls in glycerol (η = 1.4 Pa·s, ρf = 1260 kg/m³). g = 9.8 m/s². Calculate terminal velocity in m/s (3 sig figs).